# B.Com 1st Semester Business Statistics Question Papers

Table of Contents

**SUBJECT: BUSINESS STATISTICS**

**(Multiple Choice type Questions)**

Learn how you can attempt maximum test papers to improve your overall understanding of **BUSINESS STATISTICS**. It is extremely important that you revisit the concepts as most of the questions asked in these Class B.com 1st Semester **Business Statistics sample papers** are based completely on concepts.

1. The specific statistical methods that can be used to summarize or to describe a collection of

data is called:

a) Descriptive statistics

b) Inferential statistics

c) Analytical statistics

d) All of the above

2. The need for inferential statistical methods derives from the need for……………..

a) Population

b) Association

c) Sampling

d) Probability

3. A population, in statistical terms, is the totality of things under consideration. It is the

collection of all values of the…………… that is under study.

a) Instance

b) Variable

c) Amount

d) Measure

4. Non-sampling errors are introduced due to technically faulty observations or during the of

data.

a) Processing

b) Analysis

c) Sequencing

d) Collection

5. Sampling is simply a process of learning about the………

7. In statistics,……………. classification includes data according to the

time period in which the items under consideration occurred.

a) Chronological

b) Alphabetical

c) Geographical

d) Topological

8. Data is simply the numerical results of any scientific……………….

a) Analysis

b) Researches

c) Observation

d) Measurement

9. The…………… process would be required to ensure that the data is complete and as

required.

a) Tabulation

b) Analysis

c) Editing

d) Ordering

10. A sample is a portion of the ………………. population that is considered for study and

analysis.

a) Selected

b) Total

c) Fixed

d) Random

11. The standard deviation for 15, 22, 27, 11, 9, 21, 14, 9 is:

a) 6.22

b) 6.12

c) 6.04

d) 6.32

12. A student obtained the mean and the standard deviation of 100 observations as 40 and

5.1. It was later found that one observation was wrongly copied as 50, the correct figure

being 40. Find the correct mean and the S.D.

a) Mean = 38.8, S.D = 5

b) Mean = 39.9, S.D. = 5

c) Mean 39.9, S.D = 4

d) None

13. The mean deviation about median from the data: 340, 150, 210, 240, 300, 310, 320 is:

a) 51.6

b) 51.8

c) 52

d) 52.8

14. For a frequency distribution mean deviation from mean is computed by

a) JE f /J E f Idl

b) JE d /JEf

c) JE fd/ JE f

d) JEf I d I / JE f

15. The mean deviation from the median is:

a) Equal to that measured from another value

b) Maximum if all the observations are positive

c) Greater than that measured from any other value

d) Less than that measured from any value

16. The mean deviation of the series a, a + d, a +2d…… , a + 2n from its mean is

a) (n + 1) d /2n +1

b) nd /2n +1

c) n (n +1) d /2n +1

d) (2n +1) d /n (n+1)

17. A batsman score runs in 10 innings as 38, 70, 48, 34, 42, 55, 63, 46, 54 and 44. The mean

deviation about mean is

a) 8.6

b) b) 6.4

c) c) 10.6

d) d) 7.6

18. The arithmetic mean height of 50 students of a college is 5′—8′. The height of 30 of these

is given in the frequency distribution. Find the arithmetic mean height of the remaining

20 students. Height in inches: 5′—- 4″ 5′— 6″ 5′ —- 8″ 5′—-10″ 6′ — 0″Frequency:4

12482

a) 5′ —-8.8″

b) 5′ 8.0″

c) 5′ 7.8″

d) 5′ 7.0″

19. Find the sum of the deviation of the variable values 3, 4, 6, 8, 14 from their mean

a) 5

b) 0

c) 1

d) 7

20.The median of the observation 11, 12, 14, 18, x + 4, 30, 32, 35, 41 arranged in ascending

order is 24, then x is

a) 21

b) 22

c) 23

d) 24

21. A five digit number is formed using digits 1,3 5, 7 and 9 without repeating any one of

them. What is the sum of all such possible numbers?

a) 6666600

b) 6666660

c) 6666666

d) None of these

22. 139 persons have signed for an elimination tournament. All players are to be paired up for

the first round, but because 139 is an odd number one player gets a bye, which promotes

him to the second round, without actually playing in the first round. The pairing continues

on the next round, with a bye to any player left over. If the schedule is planned so that a

minimum number of matches is required to determine the champion, the number of

matches which must be played is

a) 136

b) 137

c) 138

d) 139

23. A box contains 6 red balls, 7 green balls and 5 blue balls. Each ball is of different size.

The probability that the red ball selected is the smallest red ball is

a) 1/8

b) 1/3

c) 1/6

d) 2/3

24. Boxes numbered 1,2,3,4 and 5 are kept in a row, and they which are to be filled with either a

red ball or a blue ball, such that no two adjacent boxes can be filled with blue balls. Then

how many different arrangements are possible, given that all balls of given colour are

exactly identical in all respect?

a) 8

b) 10

c) 154

d) 22

25. For a scholarship, at the most n candidates out of 2n + 1 can be selected. If the number of

different ways of selection of at least one candidate is 63, the maximum number of

candidates that can be selected for the scholarship is

a) 3

b) 4

c) 6

d) 5

26. Ten points are marked on a straight line and 11 points are marked on another straight line.

How many triangles can be constructed with vertices from among the above points?

a) 495

b) 550

c) 1045

d) 2475

27. There are three cities A, B and C. Each of these cities is connected with the other two

cities by at least one direct road. If a traveler wants to go from one city (origin) to another

city (destination), she can do so either by traversing a road connecting the two cities

directly, or by traversing two roads, the first connecting the origin to the third city and the

second connecting the third city to the destination. In all, there are 33routes from A to B

(including those via C), Similarly, there are 23 routes from B to C (including those via A).

How many roads are there from A to C directly?

a) 6

b) 3

c) 5

d) 10

28. One red flag, three white flags and two blue flags are arranged in line such that No two

adjacent flags are of the same colour. The flags at the two ends of the line are of different

colours. In how many different ways the flag be arranged?

a) 6

b) 4

c) 10

d) 2

29. Each of the 11 letters A. H, I, M, O, T, U, V, W, X and Z appears same hen looked at in

the mirror. They are called symmetric letters. Other letters in the alphabet are asymmetric

letters. How many four letter computer passwords can be formed using only the

symmetric letters ( no repetition allowed)

a) 7920

b) 330

c) 146.40

d) 419430

30. An intelligence agency forms a code of two distinct digits selected from 0, 1, 2, ………. , 9

such that the first digit of the code is non zero. The code, handwritten on the slip, can

create confusion, when read upside down for example the code 91 can be read as 16.

How many codes are there for which no such confusion can arise?

a) 80

b) 78

c) 71

d) 69

31. If the probability density of X is given by f(x) =^ 0 elsewhere and Y = X2 The probability

density of Y is

a) g(y) = e-y for y > 0 and g(y) elsewhere

b) g(y) = ey for y > 0 and g(y) = 0

c) g(y) = e-y for y< 0 and g(y) > 0

d) None of these

32. If X1 and X2 are independent random variables having exponential densities with theparameters a and b the probability density of Y = X1+ X2 when a ^ b

a) f(y) = 1/a+b. (e-y/a – e-y/b ) for y > 0 and f(y) = 0 elsewhere

b) f(y) = 1/a-b. (e-y/a – e-y/b ) for y < 0 and f(y) = 1 elsewhere

c) f(y) = 1/a-b. (e-y/a – e-y/b ) for y > 0 and f(y) = 0 elsewhere

d) None of these

33. If X is the number of head obtained in 4 tosses of a balanced coin then find the probability

distribution of the random variable Z = (X-2)2

a) z 0 1 4 h(z) 3/8 4/8 1/8

b) z 0 1 4 h(z) 1/8 4/8 1/8

c) z0 1 4 h(z) 3/8 2/8 1/8

d) z0 1 4 h(z) 3/8 7/8 1/8

34. If the joint density of X1 and X2 is given by 6e-3×1 -2×2 for x1 > 0 x2 > 0_ 0 elsewhere

Find the probability density of Y = X1+ X2

a) f(y) = 6(ey – e-3y ) for y < 0 elsewhere f(y) = 0

b) f(y) = 6(e-2y – e-3y ) for y > 0 elsewhere f(y) = 0

c) f(y) = 6(e-2y – e-y ) for y > 0 elsewhere f(y) = 1

d) f(y) = 6(e-2y – e-y/2 ) for y > 0 elsewhere f(y) = 0

35. If X has a hypergeometric distribution with M = 3, N = 6 and n = 2, find the probability

distribution of Y, the number of successes minus the number of failures

a) h(0) = 1/5 , h(1) = 3/5 , h(2) = 1/5

b) h(0) = 2/5 , h(1) = 3/8 , h(2) = 1/5

c) h(0) = 9/5 , h(1) = 3/5 , h(2) = 1/5

d) h(0) = 1/5 , h(1) = 4/5 , h(2) = 1/5

36. If the probability density is given byr f(x) = kx3 /(1 + 2x)6 for x> 0 0 elsewhere Where k is

appropriate constant the probability density of the random variable Y = 2X / 1 +2X

a) g(y) = k/16y3 .(1-y) for 0 > y > 1 and g(y) = 0 elsewhere

b) g(y) = k/16y3 .(1-y) for 0 < y < 1 and g(y) = 0 elsewhere

c) g(y) = k/16y2 .(1-y) for 0 < y < 1 and g(y) = 0 elsewhere

d) g(y) = k/16y9 .(1-y) for 0 < y < 1 and g(y) = 1 elsewhere

37. If X has the uniform density with the parameters a = 0 and P = 1. Find the probability

density of the random variable Y = VX

a) g(y) = y for 0 < y < 1 and g(y) = 0 elsewhere

b) g(y) = 2y for 0 < y < 1 and g(y) = 0 elsewhere

c) g(y) = 2y for 0 > y > 1 and g(y) = 0 elsewhere

d) None of these

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